室内可见光通信是一种利用室内照明白光LED灯来实现高速通信的新兴技术。当接收器在室内角落时较大的接收角限制了光电探测器的接收功率，从而降低了系统信噪比。为了实现接收器在室内各个位置处均能获得最大功率，提出了包含非视距链路情况下(墙壁一次反射)倾斜探测器接收面的设计方法，即在考虑视距链路(直射)的同时，还考虑了墙壁一次反射非视距链路下倾斜接收器的倾角设计。在室内各个位置处的最优倾斜角度可以通过牛顿算法得到，该快速算法的迭代次数仅为3~4次。仿真结果表明，倾斜接收器后系统最小信噪比提高大约5 dB，最大信噪比和平均信噪比均提高大约2 dB。尤其对改善室内角落处的信噪比最为显著。

Indoor visible light communication is a burgeoning technology that uses white light-emitting diodes(LED) for illumination to realize high rate communication. The receiving power of photodetector is limited when receiver is in the corners of the room due to the larger receiving angle, thus the signal to noise ratio(SNR) is decreased. The design method of tilting receiver plane was proposed to obtain the maximum in each place of the room including the Non-Line-of-Sight(NLOS) link. In this paper, the Line-of-Sight(LOS) was not only considered, but also the NLOS link was considered for the method of tilting the receiving plane. Newton method was employed to find the optimal tilting angle of receiver in each positon of the room and the iteration numbers of this algorithm were about three or four steps which was very fast. The simulation results show that the minimum SNR is increased 5 dB and the maximum and average SNR are both increased 2 dB. Especially, the SNR in the corners of the room is obviously increased.